If A + A + A = 39 B + B - A = 25 6 + C + B = 50 then A + B + C = ?? - Maths Riddles

If A + A + A = 39

B + B - A = 25

6 + C + B = 50

then

A + B + C = ??

Given A+A+A= 39

Which means 3A = 39

Now A = 39/3 = 13

We have A= 13

Now given 

B+B-A = 25

 

We can say 2B - A = 25 

Or 2B = 25+13

2B = 38

 

B = 38/2

=  19

Now we have got the values of A, B. Putting these values in the third equation we can get the value of C

6+C+B = 50

Or

6+C+19 = 50

C+25 = 50

C = 50-25

C = 25

Now,

A+B+C = 13+19+25

A+B+C = 57

Answer - 57